| Abdullah Al Mahmud | docs.statmania.info |
That branch of biometry which deals with data and laws of human mortality, morbidity, and demography.
Arthur Newsholme \(\downarrow\)
the whole study of mankind as affected by heredity or environment in so far as the results of this study can be arithmetically stated.
\[d = \frac{P_{0-14}+P_{65+}}{P_{15-64}}\times100\] Where
Age Group | Population (millions) |
---|---|
0-14 (Youth) | 40 |
15-64 (Working-Age) | 120 |
65+ (Elderly) | 20 |
Find the Dependency Ratio and explain
\[ \text{Dependency Ratio} = \left( \frac{\text{Youth} + \text{Elderly}}{\text{Working-age population}} \right) \times 100 \]
\[ \text{Dependency Ratio} = \left( \frac{40 + 20}{120} \right) \times 100 = \left( \frac{60}{120} \right) \times 100 = 50\% \]
Dependency Ratios of two different cities are
\(d_1 = 101\%\) and \(d_2 = 98\%\)
\(SR = \frac MF \times 100\)
Suppose a town has the following population data:
Males: 52,000
Females: 50,000
\[ \text{Sex Ratio} = \left( \frac{\text{Number of Males}}{\text{Number of Females}} \right) \times 100 \]
\[ \text{Sex Ratio} = \left( \frac{52,000}{50,000} \right) \times 100 = 104 \]
In this example, the sex ratio is 104, which indicates that there are 104 males for every 100 females in the town.
\(D = \frac PA\)
P = Total Population
A = Area
City | Total Population | Total Land Area (km²) |
---|---|---|
City A | 1,000,000 | 500 |
City B | 2,500,000 | 1,250 |
Find the densities
\[ \text{Population Density} = \frac{1,000,000}{500} = 2,000 \text{ people/km}^2 \]
\[ \text{Population Density} = \frac{2,500,000}{1,250} = 2,000 \text{ people/km}^2 \]
Both cities have the same population density of 2,000 people per square kilometer.
City | Total Population | Total Land Area (km²) |
---|---|---|
Tokyo, Japan | 37,435,191 | 2,194 |
New York City, USA | 8,804,190 | 783 |
Mumbai, India | 20,667,656 | 603 |
City | Population Density (people/km²) |
---|---|
Tokyo, Japan | 17,063 |
New York City, USA | 11,243 |
Mumbai, India | 34,285 |
\(CBR = \frac BP\times 1000\)
B = Total no. of alive children in a year
P = Average/Mid-year population of that region in that time
If a country has 500,000 live births in a year and a mid-year population of 50,000,000:
\[ \text{CBR} = \left( \frac{500,000}{50,000,000} \right) \times 1,000 = 10 \text{ births per 1,000 people} \]
GFR is used to estimate the number of live births in a year per 1,000 women of childbearing age (typically ages 15-49)
\(\displaystyle GFR = \frac{B}{F_{15-49}}\times 1000\)
B = Total number of live births in a year
\(F_{15-49}\) = Total number of women in reproductive age group (15-49)
A country has:
\[ \text{GFR} = \left( \frac{300,000}{10,000,000} \right) \times 1,000 = 30 \text{ births per 1,000 women} \]
ASFR is used to analyze fertility patterns across different age groups
\(\displaystyle ASFR_i = \frac{B_i}{F_i}\times 1000\)
\(B_i\) = Total number of live births in a year by the women in ith age group
\(F_i\) = No. of women in ith age group
Total Fertility Rate (TFR) of a population is the average number of children that are born to a woman over her lifetime if:
\(\displaystyle TFR = 5 \sum_{i=1}^7ASFR_i = 5 \sum_{i=1}^7 \frac{B_i}{F_i}\times 1000\)
5 for class interval
Fertility Rate | Use Case |
---|---|
GFR | Measures fertility of women aged 15-49 |
ASFR | Analyzes fertility rate specific to age groups |
TFR | Estimates total children a woman would have |
GRR | Measures the number of daughters born to women |
NRR | Measures net reproduction rate, accounting for mortality |
NFR | Measures fertility rate in a given population |
\(\displaystyle GRR = 5 \sum_{i=1}^7\frac{G_i}{F_i}\times 1000\)
\(G_i =\) Total number of girl babies born in a year by the women in ith age group
\(\displaystyle NRR = 5 \sum_{i=1}^7\frac{G_i}{F_i}\times S_i\times 1000\)
\(S_i =\) Survival rate of women of reproductive age group (15-49)
\(\displaystyle NFR = 5 \sum_{i=1}^7\frac{B_i}{F_i}\times S_i\times 1000\)
Age | # Women | # Newborn | # Baby boys | Survival probability |
---|---|---|---|---|
15-19 | 7806000 | 521435 | 272342 | 0.980 |
20-24 | 6781000 | 846256 | 422247 | 0.977 |
25-29 | 5840000 | 412342 | 206122 | 0.972 |
30-34 | 5434000 | 326268 | 183134 | 0.960 |
35-39 | 5675000 | 211810 | 111440 | 0.942 |
40-44 | 6083000 | 69750 | 34380 | 0.895 |
45-49 | 5361000 | 42354 | 22462 | 0.854 |
Total population = 109,027,142
Age Group | # Women \(\times 1000\) \(F_i\) | # Newborn \(B_i\) | # Baby boys | # Baby girls \(G_i\) | Survival probability \(S_i\) | \(ASFR_i =\) \(\frac{B_i}{F_i}\times 1000\) | \(\frac{G_i}{F_i}\) | \(\frac{G_i}{F_i}\times S_i\) |
---|---|---|---|---|---|---|---|---|
15-19 | 7806 | 521435 | 272342 | 0.980 | ||||
20-24 | 6781 | 846256 | 422247 | 0.977 | ||||
25-29 | 5840 | 412342 | 206122 | 0.972 | ||||
30-34 | 5434 | 326268 | 183134 | 0.960 | ||||
35-39 | 5675 | 211810 | 111440 | 0.942 | ||||
40-44 | 6083 | 69750 | 34380 | 0.895 | ||||
45-49 | 5361 | 42354 | 22462 | 0.854 |
NGR = CBR - CDR
\(\displaystyle \frac BP \times 1000-\frac DP \times 1000 = \frac {B-D}P \times 1000\)
\(P_o =\) Initial population
\(P_n =\) Final population
\(n =\) Number of period (year, month, etc)
\(r =\) Rate of increase
Geometric: \(P_n = P_o(1+r)^n\)
If n is fragmented in smaller periods
Like 100 % in 1 year \(\rightarrow\) 50 % in each half-year
\(P_n = P_o(1+\frac{r}{n})^n\)